Max Min Word Problems Calculus
[mage lang=”” source=”flickr”]max min word problems calculus[/mage]
Need some Math Help please….Calculus Min/Max word problems?
Find the maximum possible area of an isosceles triangle where the two equal sides are both 6 cm long.
Let the base of the triangle be 2x cm.
Then the area is y sq cm where
y = x√(36 – x²)
y’ = √(36 – x²) – x² / √(36 – x²)
.. = [36 – x² – x²] / √(36 – x²)
This has stationary values when
36 – 2x² = 0
Hence x = √18 = 3√2
When x < 3√2, y' > 0
When x > 3√2, y’ < 0
Hence x = 3√2 gives a maximum value.
Hence maximum value of y = 3√2 * √(36 - 18)
...................................... = 18
Maximum area is 18 sq cm.
Note also that the triangle with sides 6, 6, 6√2 is rightangled, and so its area is 0.5*6*6 = 18
AP Calculus Project: Application of Derivatives (Tearin’ Up My Heart)
