Differential Calculus Problems With Solution
[mage lang=”en|es|en” source=”flickr”]differential calculus problems with solution[/mage]
Calculus problem. Help with separating differential equations?
Suppose dy/dθ = y^5cosθsin^5θ.
1. Separate the differential equation, then integrate both sides.
2. Write the general solution as a function y(θ).
Help is much appreciated. Thanks!
1)
dy / dθ = y^5 cosθ sin^5θ
dy = y^5 cosθ sin^5θ dθ
(1/y^5) dy = cosθ sin^5θ dθ
That is the separation.
2)
Let’s integrate ∫cosθ sin^5θ dθ = ∫sin^5θ cosθ dθ
You will have to use integration by parts.
u = sin^5θ
du = 5(sin^4θ)cosθ dθ
dv = cosθ dθ
v = sinθ
∫u dv = uv – ∫v du
∫sin^5θ cosθ dθ = (sin^5θ)(sin^θ) – ∫sinθ*5(sin^4θ)*cosθ dθ
∫(sin^5θ)(cosθ) dθ = (sin^6θ) – 5∫(sin^5θ)(cosθ) dθ
The left side and right side have a common integral so add 5∫(sin^5θ)(cosθ) dθ to both sides.
6∫(sin^5θ)(cosθ) dθ = (sin^6θ)
Divide both sides by 6.
Thus
∫(sin^5θ)(cosθ) dθ = [(sin^6θ)/6] + C
Let’s integrate
∫(1/y^5) dy = ∫(y^-5) dy
(y^-4)/-4
Finally:
[(y^-4)/-4] = [(sin^6θ)/6] + C
You can simply further more if you like.
Differential Calculus – Basic Derivation of Polynomials – Part 1
y=[(3y+4y^2)^2-3y