Calculus Answers
What are the answers to these 2 calculus problems?
1. Find the derivative of 2^cosx. I think the answer is -sinx*2^cosx but I’m not sure.
2. What is the integral of 1/square root of e^x
Thank You
1. y = 2^cos x
dy/dx = 2^cos x • (-sin x) • ln 2 = – (ln 2) sin x 2^cos x
2. ∫ 1/√e^x dx = ∫ (e^x)^(-1/2) dx = ∫ e^(-x/2) dx = -2 e^(-x/2) + C
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