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4 thoughts on “Calculus Problem Solver”
i don’t how to use the mathway’s problem solver.
please help me in this:
2log[10](3x-2)-log[10](x+1)=1+log[10](2)
all you have to do is to solve for x
The gateway arch in St. Louis was constructed using the hyperbolic cosine function. The equation used for construction was y= 693.8597- 68.7672 cosh0.0100333x,
-299.2239 is less then or equal to x which is less then or equal to 299.2239
where x and y are measured in feet. Cross sections of the arch are equilateral triangles, and (x,y) traces the path of the centers of mass of the cross-sectional triangles. For each value of x, the area of the cross-sectional triangle is A=125.1406cosh0.0100333x
(a) How high above the ground is the center of the highest triangle? (at ground level y=0)
(b) What is the Height of the arch?
(c) How wide is the arch at ground level?
Determine the values of where the tangent line is horizontal for the function: f(x)= 1/(((x^2-1))*(x-3)) The value(s) of where the tangent line to the graph of the function is horizontal is(are)
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. I’ll bookmark your site and take the feeds also? I am happy to find numerous useful information right here within the submit, we want work out more techniques in this regard, thanks for sharing. . . . . .
i don’t how to use the mathway’s problem solver.
please help me in this:
2log[10](3x-2)-log[10](x+1)=1+log[10](2)
all you have to do is to solve for x
The gateway arch in St. Louis was constructed using the hyperbolic cosine function. The equation used for construction was y= 693.8597- 68.7672 cosh0.0100333x,
-299.2239 is less then or equal to x which is less then or equal to 299.2239
where x and y are measured in feet. Cross sections of the arch are equilateral triangles, and (x,y) traces the path of the centers of mass of the cross-sectional triangles. For each value of x, the area of the cross-sectional triangle is A=125.1406cosh0.0100333x
(a) How high above the ground is the center of the highest triangle? (at ground level y=0)
(b) What is the Height of the arch?
(c) How wide is the arch at ground level?
Determine the values of where the tangent line is horizontal for the function: f(x)= 1/(((x^2-1))*(x-3)) The value(s) of where the tangent line to the graph of the function is horizontal is(are)
Hello very cool blog!! Man .. Excellent .. Amazing .
. I’ll bookmark your site and take the feeds also? I am happy to find numerous useful information right here within the submit, we want work out more techniques in this regard, thanks for sharing. . . . . .