Answers To Calculus
How do I answer this Calculus 1 fct problem?
y=1+sqrt x
when the values of x is y=4?
for what value of x is y= 0?
for what value of x is y greater than or equal to 6?
y=1+√x
x≥0 ==> Domain=[0,∞);
x=0 ==> y=1=ymin ==> Range=[1,∞)
1) y=4 ==> 4=1+√x ==> √x=3 ==> x=9
2) y=0 is impossible (out of Range)
3) y≥6 ==> 1+√x≥6 ==> √x≥5 ==> x≥5² ==> x∈[25,∞)
Answer’s Too Low
